Evaluate using the functions \( f(x)=3 x-8 \) and \( g(x)=-x^{2}+4 x-11 \). \( \begin{array}{ll}\text { 11. } f(1)+10 & \text { 12. } g(-9)+7 \\ \text { 13. }-2 \cdot g(4) & \text { 14. }(-4)-g(7)\end{array} \) 15. Given \( f(x)=9-2 x \), if \( f(x)=19 \), find the value of \( x \).

1. For \( f(1) + 10 \): - Calculate \( f(1) \): \[ f(1) = 3(1) - 8 = 3 - 8 = -5 \] - Then: \[ f(1) + 10 = -5 + 10 = 5 \] 2. For \( g(-9) + 7 \): - Calculate \( g(-9) \): \[ g(-9) = -(-9)^2 + 4(-9) - 11 = -81 - 36 - 11 = -128 \] - Then: \[ g(-9) + 7 = -128 + 7 = -121 \] 3. For \( -2 \cdot g(4) \): - Calculate \( g(4) \): \[ g(4) = -(4)^2 + 4(4) - 11 = -16 + 16 - 11 = -11 \] - Then: \[ -2 \cdot g(4) = -2 \cdot (-11) = 22 \] 4. For \( (-4) - g(7) \): - Calculate \( g(7) \): \[ g(7) = -(7)^2 + 4(7) - 11 = -49 + 28 - 11 = -32 \] - Then: \[ (-4) - g(7) = -4 - (-32) = -4 + 32 = 28 \] 5. Given \( f(x) = 9 - 2x \) and \( f(x) = 19 \), solve for \( x \): - Set up the equation: \[ 9 - 2x = 19 \] - Subtract \( 9 \) from both sides: \[ -2x = 19 - 9 = 10 \] - Divide by \( -2 \): \[ x = \frac{10}{-2} = -5 \]