When the sample size and the sample proportion \( \overline{\text { premain the same, a } 90} \) percent confidence interval for a population proportion \( p \) will be the 99 percent confidence interval for \( p \). Multiple Choice wider than equal to
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A 90 percent confidence interval for a population proportion is narrower than a 99 percent confidence interval. This is because a higher confidence level—like 99 percent—means you want to be more certain that your interval captures the true population proportion, which requires a wider range of values to account for the increased uncertainty. So, the answer to your question is that the 90 percent confidence interval for \( p \) will be **wider than** the 99 percent confidence interval for \( p \).
