Find the \( y \)-intercept and \( x \)-intercept of the line. \[ \begin{array}{l}-4 x+5 y=7 \\ y \text {-intercept: } \square\end{array} \]

To find the \( y \)-intercept, we set \( x = 0 \) in the equation \(-4x + 5y = 7\): \[ -4(0) + 5y = 7 \implies 5y = 7 \implies y = \frac{7}{5}. \] Hence, the \( y \)-intercept is \( \frac{7}{5} \). For the \( x \)-intercept, we set \( y = 0 \) in the same equation: \[ -4x + 5(0) = 7 \implies -4x = 7 \implies x = -\frac{7}{4}. \] Thus, the \( x \)-intercept is \( -\frac{7}{4} \).