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Find the range of possible measures of the third side. Use the variable \( x \). \[ 4,7 \]

Ask by Powers Hardy. in the United States
Mar 15,2025

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The third side \( x \) must be greater than 3 and less than 11.

Solución

To find the range of possible measures for the third side \( x \) of a triangle when the other two sides are given as \( 4 \) and \( 7 \), we can use the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. Given the sides \( a = 4 \) and \( b = 7 \), we can set up the following inequalities based on the triangle inequality: 1. \( a + b > x \) 2. \( a + x > b \) 3. \( b + x > a \) Now, let's substitute the values of \( a \) and \( b \) into these inequalities: 1. \( 4 + 7 > x \) 2. \( 4 + x > 7 \) 3. \( 7 + x > 4 \) Now, we will simplify each inequality: 1. \( 11 > x \) or \( x < 11 \) 2. \( x > 3 \) 3. \( x > -3 \) (This inequality is always true since \( x \) must be positive) From the first two inequalities, we can combine them to find the range of \( x \): - From \( x < 11 \) - From \( x > 3 \) Thus, the range of possible measures for the third side \( x \) is: \[ 3 < x < 11 \] This means that \( x \) can take any value greater than \( 3 \) and less than \( 11 \).

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The Deep Dive

To find the range of possible measures for the third side \( x \) of a triangle with sides 4 and 7, we can use the triangle inequality theorem. This theorem states that the sum of the lengths of any two sides must be greater than the length of the third side. 1. For the sides 4 and \( x \): \[ 4 + x > 7 \quad \Rightarrow \quad x > 3 \] 2. For the sides 7 and \( x \): \[ 7 + x > 4 \quad \Rightarrow \quad x > -3 \] (but since \( x \) must be positive, this isn't a restriction) 3. For the sides 4 and 7: \[ 4 + 7 > x \quad \Rightarrow \quad x < 11 \] Combining these results, the range of \( x \) is: \[ 3 < x < 11 \] So, the possible measures for the third side \( x \) fall between 3 and 11.

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