Find the $$ y $$-intercept and $$ x $$-intercept of the line. $$ \begin{array}{l}x-2 y=-8 \ y \text {-intercept: } \square \ x \text {-intercept: } \square\end{array} $$

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1. **Finding the $$ y $$-intercept:**  
   To find the $$ y $$-intercept, set $$ x = 0 $$ in the equation  
   $$
   x - 2y = -8.
   $$
   Substituting $$ x = 0 $$ gives:
   $$
   0 - 2y = -8 \quad \Rightarrow \quad -2y = -8.
   $$
   Dividing both sides by $$-2$$ results in:
   $$
   y = 4.
   $$
   Thus, the $$ y $$-intercept is $$ \boxed{(0,\,4)} $$.

2. **Finding the $$ x $$-intercept:**  
   To find the $$ x $$-intercept, set $$ y = 0 $$ in the equation  
   $$
   x - 2y = -8.
   $$
   Substituting $$ y = 0 $$ gives:
   $$
   x - 2(0) = -8 \quad \Rightarrow \quad x = -8.
   $$
   Thus, the $$ x $$-intercept is $$ \boxed{(-8,\,0)} $$.
The $$ y $$-intercept is $$ (0, 4) $$ and the $$ x $$-intercept is $$ (-8, 0) $$.

Find the \( y \)-intercept and \( x \)-intercept of the line. \[ \begin{array}{l}x-2 y=-8 \\ y \text {-intercept: } \square \\ x \text {-intercept: } \square\end{array} \]

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