Evaluate each expression 37. $$ \frac{(x+3)^{2}}{x^{2}-9} $$ for $$ x=4 $$

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Substitute $$ x=4 $$ into the expression $$ \frac{(x+3)^{2}}{x^{2}-9} $$.
Evaluate the expression by following steps:
- step0: Evaluate:
  $$\frac{\left(x+3\right)^{2}}{x^{2}-9}$$
- step1: Substitute:
  $$\frac{\left(4+3\right)^{2}}{4^{2}-9}$$
- step2: Add the numbers:
  $$\frac{7^{2}}{4^{2}-9}$$
- step3: Subtract the numbers:
  $$\frac{7^{2}}{7}$$
- step4: Divide the numbers:
  $$7^{2-1}$$
- step5: Subtract the terms:
  $$7^{1}$$
- step6: Simplify:
  $$7$$
When $$ x=4 $$, the expression $$ \frac{(x+3)^{2}}{x^{2}-9} $$ evaluates to 7.
When $$ x=4 $$, the expression $$ \frac{(x+3)^{2}}{x^{2}-9} $$ equals 7.

Evaluate each expression 37. \( \frac{(x+3)^{2}}{x^{2}-9} \) for \( x=4 \)

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