Select the correct answer. Simplify the following radical expression. \( \sqrt{48} \) \( \begin{array}{ll} \)\begin{tabular}{l}\text { O } \\ \hline\end{tabular} & \( 4 \sqrt{3}\end{array} \)

When simplifying \( \sqrt{48} \), you can break it down into its prime factors. \( 48 = 16 \times 3 \) and since \( \sqrt{16} = 4 \), you can simplify it to \( \sqrt{48} = \sqrt{16 \cdot 3} = \sqrt{16} \cdot \sqrt{3} = 4\sqrt{3} \). This method of simplification is like finding the best ingredients for a recipe! When you're trying to make something delicious, you want the main flavors to shine through and not get lost in the mix. By factoring your radicals, you make sure the simplest form is what's on display! So, yes, \( \sqrt{48} = 4\sqrt{3} \) is the right choice!