Pregunta
(a) \[ \begin{aligned} 2(x+1)+3(y-1) & =12 \end{aligned} \quad x=2 \]
Ask by Barber John. in Malaysia
Jan 13,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
解为 \(x=2\) 和 \(y=3\)。
Solución
我们需要解决方程 \(2(x+1)+3(y-1) = 12\) 并且已知 \(x=2\)。
首先,将 \(x=2\) 代入方程中:
\[
2(2+1) + 3(y-1) = 12
\]
接下来,计算 \(2(2+1)\):
\[
2(3) + 3(y-1) = 12
\]
这可以简化为:
\[
6 + 3(y-1) = 12
\]
然后,减去 6:
\[
3(y-1) = 12 - 6
\]
这进一步简化为:
\[
3(y-1) = 6
\]
接下来,除以 3:
\[
y-1 = 2
\]
最后,加上 1:
\[
y = 2 + 1 = 3
\]
因此,解为 \(x=2\) 和 \(y=3\)。
Respondido por UpStudy AI y revisado por un tutor profesional
Como
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Bonus Knowledge
To solve for \(y\) using the given equation, substitute \(x = 2\) into the equation: \[ 2(2 + 1) + 3(y - 1) = 12 \] This simplifies to: \[ 2(3) + 3(y - 1) = 12 \] \[ 6 + 3(y - 1) = 12 \] Now, isolate \(3(y - 1)\): \[ 3(y - 1) = 12 - 6 \] \[ 3(y - 1) = 6 \] Now divide by 3: \[ y - 1 = 2 \] Finally, add 1 to both sides to find \(y\): \[ y = 3 \] So the solution to the equation when \(x = 2\) is \(y = 3\).

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