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(b) \( 0.3 x^{2}-0.16 x+0.25=0 \) Question 2

Ask by Cervantes George. in Papua New Guinea
Mar 20,2025

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The equation \(0.3x^{2}-0.16x+0.25=0\) has no real solutions.

Solución

Solve the equation \( 0.3x^2-0.16x+0.25=0 \). Solve the equation(The complex numbers system) by following steps: - step0: Solve using the quadratic formula in the complex numbers system: \(0.3x^{2}-0.16x+0.25=0\) - step1: Convert the decimal into a fraction: \(\frac{3}{10}x^{2}-\frac{4}{25}x+\frac{1}{4}=0\) - step2: Multiply both sides: \(100\left(\frac{3}{10}x^{2}-\frac{4}{25}x+\frac{1}{4}\right)=100\times 0\) - step3: Calculate: \(30x^{2}-16x+25=0\) - step4: Solve using the quadratic formula: \(x=\frac{16\pm \sqrt{\left(-16\right)^{2}-4\times 30\times 25}}{2\times 30}\) - step5: Simplify the expression: \(x=\frac{16\pm \sqrt{\left(-16\right)^{2}-4\times 30\times 25}}{60}\) - step6: Simplify the expression: \(x=\frac{16\pm \sqrt{-2744}}{60}\) - step7: Simplify the expression: \(x=\frac{16\pm 14\sqrt{14}\times i}{60}\) - step8: Separate into possible cases: \(\begin{align}&x=\frac{16+14\sqrt{14}\times i}{60}\\&x=\frac{16-14\sqrt{14}\times i}{60}\end{align}\) - step9: Simplify the expression: \(\begin{align}&x=\frac{4}{15}+\frac{7\sqrt{14}}{30}i\\&x=\frac{16-14\sqrt{14}\times i}{60}\end{align}\) - step10: Simplify the expression: \(\begin{align}&x=\frac{4}{15}+\frac{7\sqrt{14}}{30}i\\&x=\frac{4}{15}-\frac{7\sqrt{14}}{30}i\end{align}\) - step11: Rewrite: \(x_{1}=\frac{4}{15}-\frac{7\sqrt{14}}{30}i,x_{2}=\frac{4}{15}+\frac{7\sqrt{14}}{30}i\) - step12: Remove the complex number(s): \(\textrm{No real solution}\) The equation \(0.3x^{2}-0.16x+0.25=0\) does not have any real solutions.

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Beyond the Answer

Did you know that quadratic equations like this one have been around since ancient times? The Babylonians were solving similar equations over 4,000 years ago, although they didn't have the same notation or methods that we use today. Their techniques laid the groundwork for modern algebra, showcasing how long humans have been engaged in mathematical problem-solving! If you’re tackling this equation, it's crucial to remember the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). It helps to double-check your coefficients (in this case, \(a = 0.3\), \(b = -0.16\), and \(c = 0.25\)). Common mistakes involve incorrectly calculating the discriminant or misplacing signs, so be sure to take your time and validate each step before moving along!

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