Pregunta
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Factor: \( 36 x^{2}-49 \) (A) \( (36 x+1)(x-49) \) (B) \( (9 x-7)(4 x+7 h y \) (C) \( (6 x-7)(6 x+7) \) (D) \( (36 x-1)(36 x+1) \)

Ask by Phillips Wagner. in the United States
Mar 10,2025

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The correct factorization is \( (6x - 7)(6x + 7) \), which is choice C.

Solución

1. Recognize that the given expression \( 36x^2 - 49 \) is a difference of two perfect squares. 2. Write \( 36x^2 \) as \( (6x)^2 \) and \( 49 \) as \( 7^2 \). 3. Recall that a difference of two squares can be factored using the formula: \[ a^2 - b^2 = (a - b)(a + b) \] Here, \( a = 6x \) and \( b = 7 \). 4. Apply the formula: \[ 36x^2 - 49 = (6x - 7)(6x + 7) \] 5. The correct factorization is: \[ (6x - 7)(6x + 7) \] Thus, the answer is (C).

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The Deep Dive

To factor \( 36 x^{2}-49 \), we recognize this as a difference of squares, which has the general form \( a^2 - b^2 = (a - b)(a + b) \). Here, \( a^2 = 36x^2 \) (so \( a = 6x \)) and \( b^2 = 49 \) (so \( b = 7 \)). Thus, we rewrite it as follows: \[ 36 x^{2}-49 = (6x - 7)(6x + 7) \] Therefore, the correct answer is (C) \( (6 x-7)(6 x+7) \). For additional knowledge, let's delve into some interesting aspects! Factoring techniques, like recognizing the difference of squares, can make algebra both simpler and more delightful. It's like solving a mystery where finding the right pairs puts the pieces together and unveils a beautifully structured expression. When applying real-world math, such factoring is invaluable in areas such as physics and engineering. For instance, it can be used to simplify formulas when analyzing trajectories of projectiles or optimizing designs—which ultimately leads to more efficient solutions in everyday life!

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