Pregunta
upstudy study bank question image url

You can afford a \( \$ 200 \) per month car payment. You've found a 5 year loan at \( 5 \% \) interest. Hov big of a loan can you afford?

Ask by Stephens Estrada. in the United States
Mar 11,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

Responder

You can afford a loan of approximately \$10,646.

Solución

We start with the formula for the present value of an annuity that represents the loan amount \( L \): \[ L = P \cdot \frac{1 - \left(1 + r\right)^{-n}}{r} \] where \( P \) is the monthly payment, \( r \) is the monthly interest rate, and \( n \) is the total number of monthly payments. 1. The monthly payment is given as \( P = 200 \). 2. The annual interest rate is \( 5\% \) so the monthly rate is \[ r = \frac{0.05}{12} \approx 0.00416667. \] 3. The term of the loan is 5 years which gives \[ n = 5 \times 12 = 60 \text{ months}. \] 4. Substitute these values into the annuity formula: \[ L = 200 \cdot \frac{1 - \left(1 + 0.00416667\right)^{-60}}{0.00416667}. \] 5. Calculate \( 1 + r \): \[ 1 + 0.00416667 \approx 1.00416667. \] 6. Raise this to the \(-60\) power: \[ \left(1.00416667\right)^{-60} \approx \frac{1}{\left(1.00416667\right)^{60}}. \] Calculating \( \left(1.00416667\right)^{60} \) approximately: \[ \left(1.00416667\right)^{60} \approx 1.2834, \] so that \[ \left(1.00416667\right)^{-60} \approx \frac{1}{1.2834} \approx 0.7782. \] 7. Now evaluate the numerator: \[ 1 - 0.7782 \approx 0.2218. \] 8. Divide by \( r \): \[ \frac{0.2218}{0.00416667} \approx 53.23. \] 9. Finally, multiply by the monthly payment \( P \): \[ L \approx 200 \times 53.23 \approx 10,\!646. \] Thus, you can afford a loan of approximately \( \$10,\!646 \).

Respondido por UpStudy AI y revisado por un tutor profesional

error msg
Explicar
Simplifique esta solución

Extra Insights

To determine how big of a loan you can afford with a monthly payment of $200 for 5 years at a 5% interest rate, you can use the formula for a car loan payment: \[ P = \frac{r \times L}{1 - (1 + r)^{-n}} \] Where: - \( P \) is the monthly payment ($200), - \( L \) is the loan amount, - \( r \) is the monthly interest rate (annual rate / 12 months), and - \( n \) is the total number of payments (loan term in months). First, convert the annual interest rate to a monthly rate: \[ r = \frac{0.05}{12} \approx 0.004167 \] Then, calculate the total number of payments for 5 years: \[ n = 5 \times 12 = 60 \] Now, rearranging the formula to solve for \( L \): \[ L = \frac{P \times (1 - (1 + r)^{-n})}{r} \] Substituting the values: \[ L = \frac{200 \times (1 - (1 + 0.004167)^{-60})}{0.004167} \approx 10,739.32 \] So, you can afford a loan of approximately **$10,739.32**! To make your calculations more engaging, you could use a loan calculator available online. Just plug in your payment, interest rate, and term to instantly see your potential loan amount! Always double-check if those calculators provide a clear breakdown of your total repayment and interest paid, making it easier to understand where your money goes!

preguntas relacionadas

Latest Arithmetic Questions

¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde Hazte Premium
Estudiar puede ser una verdadera lucha
¿Por qué no estudiarlo en UpStudy?
Seleccione su plan a continuación
Prima

Puedes disfrutar

Empieza ahora
  • Explicaciones paso a paso
  • Tutores expertos en vivo 24/7
  • Número ilimitado de preguntas
  • Sin interrupciones
  • Acceso completo a Respuesta y Solución
  • Acceso completo al chat de PDF, al chat de UpStudy y al chat de navegación
Básico

Totalmente gratis pero limitado

  • Solución limitada
Bienvenido a ¡Estudia ahora!
Inicie sesión para continuar con el recorrido de Thoth AI Chat
Continuar con correo electrónico
O continuar con
Al hacer clic en "Iniciar sesión", acepta nuestros términos y condiciones. Términos de Uso & Política de privacidad