20. Suppose \( \xi=\{x: x \) is an integer such that \( 0
Ask by Spencer Bowers. in Singapore
Mar 20,2025
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Extra Insights
Let's unwrap this set theory conundrum in a fun way! For part (a), the fun begins with the elements of \( A \). Since \( A = \{ x : 5x < 38 \} \), we can derive \( x < \frac{38}{5} = 7.6 \). Considering \( x \) must be an integer, \( A = \{ 1, 2, 3, 4, 5, 6, 7 \} \). Now, onto \( B \): \( B = \{ x : 2 < x < 7 \} \) gives us \( B = \{ 3, 4, 5, 6 \} \). For part (b), let's dive into the relationship! We can see that elements of \( B \) (3, 4, 5, 6) are also in \( A \). This tells us that \( B \subset A \). In other words, set \( B \) is fully contained within set \( A \), meaning every element of \( B \) can be found in \( A \) – talk about a cozy relationship! Now, for part (c), imagine a Venn diagram! Picture a rectangle representing set \( \xi \) with integers from 1 to 10 dancing around. Inside this rectangle, there's a circle for set \( A \) from 1 to 7, with an inner circle for set \( B \) showing 3, 4, 5, and 6. You’ll see that \( B \) sits snugly inside \( A \), while numbers like 1, 2, 7, 8, 9, and 10 remain outside. It's like a little math community where all are welcome!
