1. Solve the inequality: $$ \frac{y+3}{5} \geq \frac{y+2}{3}+2 $$

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Solve the equation $$ \frac{y+3}{5} \geq \frac{y+2}{3}+2 $$.
Solve the inequality by following steps:
- step0: Solve for $$y$$:
  $$\frac{y+3}{5}\geq \frac{y+2}{3}+2$$
- step1: Multiply both sides:
  $$\frac{y+3}{5}	imes 15\geq \left(\frac{y+2}{3}+2ight)	imes 15$$
- step2: Multiply the terms:
  $$3y+9\geq 5y+10+30$$
- step3: Simplify:
  $$3y+9\geq 5y+40$$
- step4: Move the expression to the left side:
  $$3y-5y\geq 40-9$$
- step5: Add and subtract:
  $$-2y\geq 40-9$$
- step6: Add and subtract:
  $$-2y\geq 31$$
- step7: Change the signs:
  $$2y\leq -31$$
- step8: Divide both sides:
  $$\frac{2y}{2}\leq \frac{-31}{2}$$
- step9: Divide the numbers:
  $$y\leq -\frac{31}{2}$$
The solution to the inequality $$ \frac{y+3}{5} \geq \frac{y+2}{3}+2 $$ is $$ y \leq -\frac{31}{2} $$.
$$ y \leq -\frac{31}{2} $$

Solve the inequality:

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