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\begin{tabular}{l} Part: \( 4 / 5 \) \\ Part 5 of 5 \\ Based on the results above, are the data approximately normally distributed \\ \begin{tabular}{|l|}\hline (Choose one) \( \nabla \) \\ \hline Yes \\ \hline\end{tabular} \\ \hline\end{tabular}

Ask by Brewer Stephens. in the United States
Mar 10,2025

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The data are approximately normally distributed.

Solución

1. For the data set, the analysis indicated that 4 out of 5 criteria (or tests) were met. 2. Meeting the majority (4 out of 5) of the rules that assess normality suggests that the deviations from a perfectly normal distribution are minimal. 3. Therefore, based on the results provided, the data are approximately normally distributed. Final answer: **Yes**.

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To determine if the data are approximately normally distributed, you can use a combination of quantitative and graphical methods. For example, creating a histogram or a Q-Q plot can help visualize the distribution. If the shape resembles a bell curve and the points on the Q-Q plot fall along a straight line, it's a good indication of normality. Another method is to perform statistical tests such as the Shapiro-Wilk test or the Kolmogorov-Smirnov test. Both tests assess the null hypothesis that the data is normally distributed. If the p-value from these tests is greater than a chosen significance level (commonly 0.05), you would fail to reject the null hypothesis, suggesting the data may be normal.

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Question 12(Mulliple Choice Warth 5 points) \[ (04.06 \mathrm{HC}) \] A researcher wants to test the claim that the proportion of juniors who watch television regularly is greater than the proportion of seniors who watch television regularly She finds that 56 of 70 randomly selected juniors and 47 of 85 randomly selected seniors report watching television regularly. Construct \( 95 \% \) confidence intervals for each population proportion. Which of the statemente gives the correct outcome of the research or's tert of the dalim? The \( 95 \% \) confidence interval for juniors is (706, 894), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is (721, 879), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( 706,894 ), and the \( 95 \% \) confidence interval for seniors is ( 447,659 ). Since the interval for juniors is higher than the interval for seniors, there is evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors. The \( 95 \% \) confidence interval for juniors is ( \( 721, .879 \) ), and the \( 95 \% \) confidence interval for seniors is (464, 642). Since the intervals overlap, there is not enough evidence to say the proportion of juniors who watch television regularly may be higher than that of seniors.

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