e) \( \left(-1 \frac{1}{3}+\frac{7}{8}\right)+\frac{2}{3} \)
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Beyond the Answer
To solve the expression \( \left(-1 \frac{1}{3}+\frac{7}{8}\right)+\frac{2}{3} \), we first convert \(-1 \frac{1}{3}\) into an improper fraction. It becomes \(-\frac{4}{3}\). So we rewrite the expression as: \[ \left(-\frac{4}{3} + \frac{7}{8}\right) + \frac{2}{3} \] Next, let's find a common denominator to combine \(-\frac{4}{3}\) and \(\frac{7}{8}\). The least common multiple of 3 and 8 is 24. Rewriting the fractions, we have: \(-\frac{4}{3} = -\frac{32}{24}\) and \(\frac{7}{8} = \frac{21}{24}\). Now, we combine these: \[ -\frac{32}{24} + \frac{21}{24} = -\frac{32 - 21}{24} = -\frac{11}{24} \] Now we add \(\frac{2}{3}\) to \(-\frac{11}{24}\). We need to convert \(\frac{2}{3}\) to a fraction with a denominator of 24: \(\frac{2}{3} = \frac{16}{24}\). Now we can add: \[ -\frac{11}{24} + \frac{16}{24} = \frac{16 - 11}{24} = \frac{5}{24} \] Thus, the final answer is: \[ \frac{5}{24} \]
