Find \( (f \circ g)(0) \) \( f(x)=x+1 \) and \( g(x)=4 x+6 \)

To find \( (f \circ g)(0) \), we first need to evaluate \( g(0) \) using the function \( g(x) = 4x + 6 \). Calculating \( g(0) \): \[ g(0) = 4(0) + 6 = 6 \] Now that we have \( g(0) = 6 \), we can plug this value into the function \( f(x) = x + 1 \). Calculating \( f(g(0)) = f(6) \): \[ f(6) = 6 + 1 = 7 \] Thus, \( (f \circ g)(0) = 7 \).