Find the general solution for: \[ \sin y+1,5=2,01 \] INSTRUCTION: Round your answers to one decimal place, and if there is more than one answer, separate the answers with " ; " like this: \[ 15,4+360 k ; 164,6+360 k \]

To solve the equation \(\sin y + 1.5 = 2.01\), we first isolate \(\sin y\): \[ \sin y = 2.01 - 1.5 = 0.51 \] Now we need to find the angles \(y\) for which \(\sin y = 0.51\). Using the inverse sine function, we get the principal solution: \[ y = \arcsin(0.51) \approx 30.7^\circ \] Since the sine function is positive in both the first and second quadrants, we can find the second solution: \[ y = 180^\circ - 30.7^\circ \approx 149.3^\circ \] The general solutions include all angles that fit these results, along with the periodicity of the sine function, which is \(360^\circ\). Thus, the general solution is: \[ 30.7 + 360k ; 149.3 + 360k \] where \(k\) is any integer.