Question Find the product of the following two matrices. \[ \left[\begin{array}{ccc}0 & -4 & -4 \\ -5 & 0 & 4\end{array}\right]\left[\begin{array}{cc}0 & -1 \\ 2 & 0 \\ -2 & 1\end{array}\right] \]
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To find the product of the given matrices, we will multiply the first matrix, which is a 2x3 matrix, by the second matrix, which is a 3x2 matrix. The resulting product will be a 2x2 matrix. Let’s denote the matrices as follows: \[ A = \left[\begin{array}{ccc}0 & -4 & -4 \\ -5 & 0 & 4\end{array}\right] \] \[ B = \left[\begin{array}{cc}0 & -1 \\ 2 & 0 \\ -2 & 1\end{array}\right] \] Now, we compute the product \( C = A \times B \). The element \( C_{11} \) is calculated as follows: \[ C_{11} = 0 \cdot 0 + (-4) \cdot 2 + (-4) \cdot (-2) = 0 - 8 + 8 = 0 \] The element \( C_{12} \) is calculated as: \[ C_{12} = 0 \cdot (-1) + (-4) \cdot 0 + (-4) \cdot 1 = 0 + 0 - 4 = -4 \] Now, for the second row of matrix \( C \): The element \( C_{21} \) is calculated as: \[ C_{21} = (-5) \cdot 0 + 0 \cdot 2 + 4 \cdot (-2) = 0 + 0 - 8 = -8 \] The element \( C_{22} \) is calculated as: \[ C_{22} = (-5) \cdot (-1) + 0 \cdot 0 + 4 \cdot 1 = 5 + 0 + 4 = 9 \] Putting it all together, the resulting product matrix \( C \) is: \[ C = \left[\begin{array}{cc}0 & -4 \\ -8 & 9\end{array}\right] \] So, the product of the two matrices is: \[ \left[\begin{array}{cc}0 & -4 \\ -8 & 9\end{array}\right] \]
