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Question Find the product of the following two matrices. \[ \left[\begin{array}{ccc}0 & -4 & -4 \\ -5 & 0 & 4\end{array}\right]\left[\begin{array}{cc}0 & -1 \\ 2 & 0 \\ -2 & 1\end{array}\right] \]

Ask by Boyd Savage. in the United States
Mar 11,2025

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The product of the two matrices is: \[ \left[\begin{array}{ll}0 & -4 \\ -8 & 9\end{array}\right] \]

Solución

To find the product of two matrices, we need to follow the rules of matrix multiplication. Given matrices: \[ A = \left[\begin{array}{ccc}0 & -4 & -4 \\ -5 & 0 & 4\end{array}\right] \] \[ B = \left[\begin{array}{cc}0 & -1 \\ 2 & 0 \\ -2 & 1\end{array}\right] \] The product of matrices A and B is denoted as AB. To find the product AB, we need to perform the following steps: 1. Multiply the rows of matrix A with the columns of matrix B. 2. The resulting product will be a matrix with the same number of rows as matrix A and the same number of columns as matrix B. Let's calculate the product AB step by step. Matrices by following steps: - step0: Solution: \(\left[\begin{array}{lll}{0}&{-4}&{-4}\\{-5}&{0}&{4}\end{array}\right]\times \left[\begin{array}{ll}{0}&{-1}\\{2}&{0}\\{-2}&{1}\end{array}\right]\) - step1: Multiply the terms: \(\left[\begin{array}{ll}{0\times 0-4\times 2-4\left(-2\right)}&{0\times \left(-1\right)-4\times 0-4\times 1}\\{-5\times 0+0\times 2+4\left(-2\right)}&{-5\left(-1\right)+0\times 0+4\times 1}\end{array}\right]\) - step2: Evaluate: \(\left[\begin{array}{ll}{0}&{-4}\\{-8}&{9}\end{array}\right]\) The product of the two matrices is: \[ AB = \left[\begin{array}{ll}0 & -4 \\ -8 & 9\end{array}\right] \]

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To find the product of the given matrices, we will multiply the first matrix, which is a 2x3 matrix, by the second matrix, which is a 3x2 matrix. The resulting product will be a 2x2 matrix. Let’s denote the matrices as follows: \[ A = \left[\begin{array}{ccc}0 & -4 & -4 \\ -5 & 0 & 4\end{array}\right] \] \[ B = \left[\begin{array}{cc}0 & -1 \\ 2 & 0 \\ -2 & 1\end{array}\right] \] Now, we compute the product \( C = A \times B \). The element \( C_{11} \) is calculated as follows: \[ C_{11} = 0 \cdot 0 + (-4) \cdot 2 + (-4) \cdot (-2) = 0 - 8 + 8 = 0 \] The element \( C_{12} \) is calculated as: \[ C_{12} = 0 \cdot (-1) + (-4) \cdot 0 + (-4) \cdot 1 = 0 + 0 - 4 = -4 \] Now, for the second row of matrix \( C \): The element \( C_{21} \) is calculated as: \[ C_{21} = (-5) \cdot 0 + 0 \cdot 2 + 4 \cdot (-2) = 0 + 0 - 8 = -8 \] The element \( C_{22} \) is calculated as: \[ C_{22} = (-5) \cdot (-1) + 0 \cdot 0 + 4 \cdot 1 = 5 + 0 + 4 = 9 \] Putting it all together, the resulting product matrix \( C \) is: \[ C = \left[\begin{array}{cc}0 & -4 \\ -8 & 9\end{array}\right] \] So, the product of the two matrices is: \[ \left[\begin{array}{cc}0 & -4 \\ -8 & 9\end{array}\right] \]

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