Find the \( 10^{\text {th }} \) term of the geometric sequence ( 2 mks ). \( 16,8,4,2,1, \ldots \ldots \ldots . . . . . . . . \).
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To find the \( 10^{\text{th}} \) term of the geometric sequence \( 16, 8, 4, 2, 1, \ldots \), we first identify the first term \( a \) and the common ratio \( r \). The first term \( a = 16 \) and the second term is \( 8 \). To find the common ratio \( r \), we divide the second term by the first term: \[ r = \frac{8}{16} = \frac{1}{2}. \] The formula for the \( n^{\text{th}} \) term of a geometric sequence is given by: \[ a_n = a \cdot r^{n-1}. \] For the \( 10^{\text{th}} \) term (\( n = 10 \)): \[ a_{10} = 16 \cdot \left(\frac{1}{2}\right)^{10-1} = 16 \cdot \left(\frac{1}{2}\right)^{9} = 16 \cdot \frac{1}{512} = \frac{16}{512} = \frac{1}{32}. \] Thus, the \( 10^{\text{th}} \) term of the sequence is \( \frac{1}{32} \).
