\( \frac { ( 0,5 ) ^ { - 2 } \cdot 2 ^ { 0,333 \ldots } \cdot \sqrt[ 3 ] { 16 } } { ( 0,125 ) ^ { - 3 } } \)
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Let's break it down! First, let's simplify the expression step by step. The expression is: \[ \frac { ( 0,5 ) ^ { - 2 } \cdot 2 ^ { 0,333 \ldots } \cdot \sqrt[ 3 ] { 16 } } { ( 0,125 ) ^ { - 3 } } \] Starting with \((0,5)^{-2}\): \((0,5)^{-2} = (2)^{2} = 4\) Then, \(2^{0.333...\) can be recognized as \(2^{1/3}\) which is the cube root of 2: \(2^{0,333...} = \sqrt[3]{2}\) Next, simplifying \(\sqrt[3]{16}\): \(\sqrt[3]{16} = \sqrt[3]{2^4} = 2^{4/3}\) Now, let's address \((0,125)^{-3}\): \((0,125)^{-3} = (2^{-3})^{-3} = 2^{9} = 512\) Putting everything together, the numerator is: \[ 4 \cdot 2^{1/3} \cdot 2^{4/3} = 4 \cdot 2^{(1/3 + 4/3)} = 4 \cdot 2^{5/3} \] Now, let's express the numerator: \[ 4 = 2^2 \Rightarrow 2^2 \cdot 2^{5/3} = 2^{(2 + 5/3)} = 2^{(6/3 + 5/3)} = 2^{11/3} \] Finally, putting it all into the original expression: \[ \frac{2^{11/3}}{512} = \frac{2^{11/3}}{2^9} = 2^{(11/3 - 27/3)} = 2^{-16/3} \] Thus, the final simplified result is: \[ 2^{-16/3} \text{ or } \frac{1}{2^{16/3}} \text{ or } \frac{1}{\sqrt[3]{65536}}. \] So, your answer is: \[ \frac{1}{2^{16/3}} \text{ or } 2^{-16/3}. \]
