$$ 1 \in $$ Factor the difference of two squares. $$ 16 x^{2}-81 $$ Select the correct choice below and, if necessary, fill in the answer box within your choice. A. $$ 16 x^{2}-81=\square $$ B. The polynomial is prime.

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To factor the expression $$ 16x^{2} - 81 $$ as a difference of two squares, follow these steps:

1. **Identify the squares:**
   $$
   16x^{2} = (4x)^{2} \quad \text{and} \quad 81 = 9^{2}
   $$

2. **Apply the difference of squares formula:**
   $$
   a^{2} - b^{2} = (a - b)(a + b)
   $$
   
   Here, $$ a = 4x $$ and $$ b = 9 $$.

3. **Factor the expression:**
   $$
   16x^{2} - 81 = (4x - 9)(4x + 9)
   $$

**Correct Choice:**

**A.** $$ 16x^{2} - 81 = (4x - 9)(4x + 9) $$
$$ 16x^{2} - 81 = (4x - 9)(4x + 9) $$

\( 1 \in \) Factor the difference of two squares. \( 16 x^{2}-81 \) Select the correct choice below and, if necessary, fill in the answer box within your choice. A. \( 16 x^{2}-81=\square \) B. The polynomial is prime.

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