1 Within cells, small organelles containing newly synthesized proteins are transported along microtubules by tiny molecular motors called kinesins. What force does a kinesin molecule need to deliver in order to accelerate an organelle with mass \( 1.00 \times 10^{-17} \mathrm{~kg} \) from 0 to \( 8.70 \mu \mathrm{~m} / \mathrm{s} \) within a time of \( 10.0 \mu \mathrm{~s} \) ? \( \square \mathrm{N} \)
Solución de inteligencia artificial de Upstudy
Responder
Solución

¡Inicia sesión para desbloquear respuestas gratis!
Una plataforma de aprendizaje en la que confían millones de estudiantes y profesores reales.

Respondido por UpStudy AI y revisado por un tutor profesional
Extra Insights
To determine the force required by the kinesin molecule to accelerate the organelle, we first need to calculate the acceleration. We can use the formula: \[ a = \frac{\Delta v}{\Delta t} \] where \( \Delta v = 8.70 \, \mu m/s = 8.70 \times 10^{-6} \, m/s \) and \( \Delta t = 10.0 \, \mu s = 10.0 \times 10^{-6} \, s \). Calculating the acceleration: \[ a = \frac{8.70 \times 10^{-6} \, m/s}{10.0 \times 10^{-6} \, s} = 0.870 \, m/s^2 \] Next, we can find the force using Newton's second law: \[ F = m \cdot a \] where \( m = 1.00 \times 10^{-17} \, kg \). So, \[ F = 1.00 \times 10^{-17} \, kg \times 0.870 \, m/s^2 = 8.70 \times 10^{-18} \, N \] Thus, the force that the kinesin molecule needs to deliver is \( 8.70 \times 10^{-18} \, N \).
