Pregunta
upstudy study bank question image url

4. A chemist carries out an experiment to determine the number of moles of \( \mathrm{Cl}^{-} \)ions in a 1 L sample of water. The salt water reacts with excess \( \mathrm{AgNO}_{3} \) solution. The resulting precipitate is collected, dried and weighed. The mass of the AgCl precipitate is found to be 5.4 g . The chemical equation for the reaction is: \[ \mathrm{AgNO}_{3}(a q)+\mathrm{NaCl}(a q) \rightarrow \mathrm{AgCl}(s)+\mathrm{NaNO}_{3}(a q) \] Calculate the moles of \( \mathrm{Cl}^{-} \)ions in the sample, and describe how the number of moles was found. Re to the periodic table.

Ask by Ramirez Wang. in the United States
Mar 11,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

Responder

The number of moles of \( \mathrm{Cl}^{-} \) ions in the sample is approximately 0.0377 moles.

Solución

¡Inicia sesión para desbloquear respuestas gratis!

Una plataforma de aprendizaje en la que confían millones de estudiantes y profesores reales.

star-icon Descubrir

Respondido por UpStudy AI y revisado por un tutor profesional

The Deep Dive

To find the moles of \( \mathrm{Cl}^{-} \) ions in the sample, we first need to determine the number of moles of the precipitate \( \mathrm{AgCl} \). The molar mass of \( \mathrm{AgCl} \) is approximately 143.32 g/mol (with silver \( \mathrm{Ag} \) being about 107.87 g/mol and chlorine \( \mathrm{Cl} \) being about 35.45 g/mol). Using the mass of \( \mathrm{AgCl} \) precipitate, we calculate the moles: \[ \text{Moles of } \mathrm{AgCl} = \frac{\text{mass}}{\text{molar mass}} = \frac{5.4 \, \text{g}}{143.32 \, \text{g/mol}} \approx 0.0376 \, \text{mol} \] Because the reaction shows a 1:1 stoichiometry between \( \mathrm{Cl}^- \) and \( \mathrm{AgCl} \), the moles of \( \mathrm{Cl}^- \) ions in the sample are also approximately 0.0376 mol. Understanding the stoichiometry of reactions is crucial, as it helps chemists quantify reactants and products. For instance, in this case, each mole of \( \mathrm{Cl}^- \) generates one mole of precipitate \( \mathrm{AgCl} \). This fundamental principle underlies many laboratory analyses in chemistry and ensures accurate interpretations of experimental results. Using precise measurements and calculations is key in lab work. A common mistake is improperly converting grams to moles due to incorrect molar masses or unit confusion. Always double-check calculations, especially when measuring sample weights or balancing equations. This ensures the integrity of your results, which is especially important when determining concentrations or moles in a solution.

preguntas relacionadas

Latest Chemistry Questions

¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde Hazte Premium
Estudiar puede ser una verdadera lucha
¿Por qué no estudiarlo en UpStudy?
Seleccione su plan a continuación
Prima

Puedes disfrutar

Empieza ahora
  • Explicaciones paso a paso
  • Tutores expertos en vivo 24/7
  • Número ilimitado de preguntas
  • Sin interrupciones
  • Acceso completo a Respuesta y Solución
  • Acceso completo al chat de PDF, al chat de UpStudy y al chat de navegación
Básico

Totalmente gratis pero limitado

  • Solución limitada
Bienvenido a ¡Estudia ahora!
Inicie sesión para continuar con el recorrido de Thoth AI Chat
Continuar con correo electrónico
O continuar con
Al hacer clic en "Iniciar sesión", acepta nuestros términos y condiciones. Términos de Uso & Política de privacidad