Add. Assume that all variables represent positive real numbers. \( \frac{\sqrt[3]{8 x^{4}}}{13}+\frac{4 x \sqrt[3]{x}}{13} \) \( \frac{\sqrt[3]{8 x^{4}}}{13}+\frac{4 x \sqrt[3]{x}}{13}=\square \) (Simplify your answer. Type an exact answer, using radicals as needed.)

To simplify the expression \(\frac{\sqrt[3]{8 x^{4}}}{13}+\frac{4 x \sqrt[3]{x}}{13}\), we start with each term. The first term is: \[ \frac{\sqrt[3]{8 x^{4}}}{13} = \frac{\sqrt[3]{8} \sqrt[3]{x^{4}}}{13} = \frac{2 \cdot x^{4/3}}{13} = \frac{2 x^{4/3}}{13} \] The second term is: \[ \frac{4 x \sqrt[3]{x}}{13} = \frac{4 x^{1} x^{1/3}}{13} = \frac{4 x^{(1 + 1/3)}}{13} = \frac{4 x^{4/3}}{13} \] Now we add the two terms together: \[ \frac{2 x^{4/3}}{13} + \frac{4 x^{4/3}}{13} = \frac{(2 + 4) x^{4/3}}{13} = \frac{6 x^{4/3}}{13} \] Therefore, the simplified expression is: \[ \frac{6 x^{4/3}}{13} = \square \] So, the final answer is: \[ \frac{6 x^{4/3}}{13} \]