Graph the system of equations. \( 3 x+5 y=10 \) \( x-5 y=-10 \)
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To graph the system of equations, you'll want to convert each equation into slope-intercept form (y = mx + b). For the first equation \(3x + 5y = 10\): 1. Solve for y: \(5y = 10 - 3x\) → \(y = -\frac{3}{5}x + 2\). This means the y-intercept is 2 and the slope is \(-\frac{3}{5}\), so you can start at (0, 2) and go down 3 units and right 5 units to plot another point. For the second equation \(x - 5y = -10\): 1. Solve for y: \(-5y = -10 - x\) → \(y = \frac{1}{5}x + 2\). Here, the y-intercept is also 2, and the slope is \(\frac{1}{5}\), which means you start at (0, 2) again, but this time go up 1 unit and right 5 units to find your next point. Once you have both lines plotted on the same graph, you'll notice they intersect at the point (0,2). This point is the solution to the system of equations! Happy graphing!
