What is the probability of getting a 5 and then a 2 with the normal 6 -sided die? (answer in fraction) Type a response

To find the probability of getting a 5 and then a 2 when rolling a normal 6-sided die, we can follow these steps: 1. **Determine the probability of rolling a 5.** - There is 1 favorable outcome (rolling a 5) out of 6 possible outcomes (1, 2, 3, 4, 5, 6). - Therefore, the probability \( P(5) \) is: \[ P(5) = \frac{1}{6} \] 2. **Determine the probability of rolling a 2.** - Similarly, there is 1 favorable outcome (rolling a 2) out of 6 possible outcomes. - Therefore, the probability \( P(2) \) is: \[ P(2) = \frac{1}{6} \] 3. **Calculate the combined probability of both events occurring in sequence.** - Since the rolls are independent, we multiply the probabilities: \[ P(5 \text{ and then } 2) = P(5) \times P(2) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} \] Thus, the probability of rolling a 5 and then a 2 with a normal 6-sided die is \(\frac{1}{36}\).