Estimate \( \sqrt{50} \) to the hundredths place. 1. Estimate between two whole numbers: \( 7^{2}=49,8^{2}=64 \) 2. Estimate further to the tenths place: \( 7.0^{2}=49.0,7.1^{2}=50.41 \) 3. Estimate further to the hundredths place: The \( \sqrt{50} \) is between

7.0 and 7.1, but since \( 7.1^2 \) is greater than 50, let's narrow it down further. Testing \( 7.05^2 \), we find \( 7.05^2 = 49.7025 \), which is less than 50, and testing \( 7.06^2 \), we find \( 7.06^2 = 49.8436 \), still less than 50. Continuing this process, testing \( 7.07^2 \) gives us \( 7.07^2 = 49.9849 \), which is also less than 50. However, \( 7.08^2 \) equals \( 50.5664 \), confirming that we found our range. Based on this information, we can estimate that \( \sqrt{50} \) is approximately between 7.07 and 7.08, leaning more towards around \( 7.07 \) for the hundredths place, so \( \sqrt{50} \approx 7.07 \).