Question 8 Solve the equation \( 4^{(x+5)}=7^{(x-2)} \). Leave your answer in terms of logarithms (do not provide a decimal answer).
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To solve the equation \( 4^{(x+5)}=7^{(x-2)} \), we can start by taking the logarithm of both sides: \[ \log(4^{(x+5)}) = \log(7^{(x-2)}) \] Using the power rule of logarithms, we can rewrite this as: \[ (x+5) \log(4) = (x-2) \log(7) \] Next, distribute the logarithms: \[ x \log(4) + 5 \log(4) = x \log(7) - 2 \log(7) \] Now, rearranging the equation to isolate \(x\): \[ x \log(4) - x \log(7) = -2 \log(7) - 5 \log(4) \] Factor out \(x\) on the left side: \[ x (\log(4) - \log(7)) = -2 \log(7) - 5 \log(4) \] Finally, solve for \(x\): \[ x = \frac{-2 \log(7) - 5 \log(4)}{\log(4) - \log(7)} \] So, the solution to the equation is: \[ x = \frac{-2 \log(7) - 5 \log(4)}{\log(4) - \log(7)} \]
