Pregunta
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\begin{tabular}{l} Is \( \sqrt{7} \) a rational number? \\ yes no \\ \hline\end{tabular}

Ask by Valdez Best. in the United States
Feb 28,2025

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√7 is not a rational number.

Solución

The answer is no. To explain briefly: If √7 were a rational number, it could be expressed as a fraction p/q in lowest terms. Squaring both sides gives 7 = p²/q², which implies p² = 7q². This means that p² (and hence p) is divisible by 7. If p is divisible by 7, then so is q, contradicting the assumption that the fraction p/q is in lowest terms. Therefore, √7 cannot be rational—it is irrational.

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The Deep Dive

To determine whether \( \sqrt{7} \) is a rational number, we first need to know that a rational number can be expressed as a fraction of two integers, where the denominator is not zero. Since \( \sqrt{7} \) cannot be expressed this way, it is classified as an irrational number. It has a non-repeating, non-terminating decimal expansion, approximately equal to 2.6457513110645906. Interestingly, the concept of irrational numbers was first introduced by the ancient Greeks when they encountered the square root of 2, which was notably controversial at the time. The discovery of irrational numbers expanded the realm of mathematics and led to further developments in algebra, geometry, and number theory, reshaping our understanding of numbers forever!

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