Use the quadratic formula to solve the equation. \( 3 x^{2}=3-3 x \) The solution set is of (Simplify your answer. Type an exact answer, using radicals and \( i \) as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)

1. Begin with the equation: \[ 3x^2 = 3 - 3x \] 2. Rearrange the equation by bringing all terms to one side: \[ 3x^2 + 3x - 3 = 0 \] 3. Divide every term by 3 to simplify: \[ x^2 + x - 1 = 0 \] 4. Identify the coefficients for the quadratic equation \(ax^2 + bx + c = 0\): \[ a = 1, \quad b = 1, \quad c = -1 \] 5. Apply the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] 6. Substitute the values of \(a\), \(b\), and \(c\): \[ x = \frac{-1 \pm \sqrt{1^2 - 4(1)(-1)}}{2(1)} = \frac{-1 \pm \sqrt{1 + 4}}{2} \] 7. Simplify inside the square root: \[ x = \frac{-1 \pm \sqrt{5}}{2} \] 8. Therefore, the solution set is: \[ \frac{-1+\sqrt{5}}{2}, \quad \frac{-1-\sqrt{5}}{2} \]