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A meteorologist found that the rainfall in Centerville during the first half of the month was \( 3 / 5 \) of an inch. At the end of the month, he found that the total rainfall for the month was \( 7 / 10 \) of an inch. How much did it rain in the second half of the month? Write your answer as a fraction or as a whole or mixed number.

Ask by Reid Hobbs. in the United States
Feb 25,2025

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It rained \( \frac{1}{10} \) of an inch in the second half of the month.

Solución

The total rainfall for the month was 7/10 inch, and during the first half it was 3/5 inch. To find the rainfall for the second half, subtract the first half's rainfall from the total:   Second half rainfall = (7/10) − (3/5) Since 3/5 is equivalent to 6/10, we have:   Second half rainfall = (7/10) − (6/10) = 1/10 So, it rained 1/10 of an inch in the second half of the month.

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To find out how much it rained in the second half of the month, we need to subtract the rainfall during the first half from the total rainfall for the month. Total rainfall for the month: \( \frac{7}{10} \) inch Rainfall during the first half: \( \frac{3}{5} \) inch First, we need to express \( \frac{3}{5} \) with a denominator of 10 to perform the subtraction: \[ \frac{3}{5} = \frac{3 \times 2}{5 \times 2} = \frac{6}{10} \] Now, subtract the first half from the total rainfall: \[ \frac{7}{10} - \frac{6}{10} = \frac{1}{10} \] Thus, it rained \( \frac{1}{10} \) of an inch in the second half of the month.

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