Pregunta
Solve the equation and inequalities. Write the solution sets in interval notation if possible.
(a)
(b)
©
(d)
(e)
(a)
(b)
©
(d)
(e)
Ask by Pope French. in the United States
Mar 19,2025
Solución de inteligencia artificial de Upstudy
Respuesta verificada por el tutor
Responder
(a)
or
(b)
©
(d)
or
(e)
or
Solución
(a) Solve
For a product to equal zero, one of the factors must be zero.
- Set the first factor equal to zero:
- Set the second factor equal to zero:
Solution set:
(b) Solve
A product is negative when the factors have opposite signs. The critical points are
and
. These divide the real line into three intervals.
-
Interval
: Choose: Product:(positive). -
Interval
: Choose: Product:(negative). -
Interval
: Choose: Product:(positive).
The inequality
holds when the product is negative.
Solution set:
© Solve
This inequality is similar to part (b), but includes the points where the expression equals zero. From part (a), these points are
and
.
Solution set:
(d) Solve
Here, we need the product to be positive. From our sign analysis in part (b):
- For
, the product is positive. - For
, the product is positive.
Solution set:
(e) Solve
This inequality requires the product to be positive or zero. In addition to the positive intervals from part (d), we include the zeros at
and
.
Solution set:
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Bonus Knowledge
To solve the equation and inequalities you’ve provided, let’s first find the roots of the equation
.
(a) Set each factor to zero:
-
→ -
→
The solutions to the equation are
and
. In interval notation, this can be expressed as
.
(b) Now, let’s solve the inequality
. We analyze the intervals determined by the roots:
- Test intervals:
, , and .
-
Choose a number from
, say :
→ doesn’t satisfy. -
Choose from
, let’s try :
→ satisfies. -
Choose from
, let :
→ doesn’t satisfy.
Thus, the solution for
is:
.
© For
, we include the endpoints:
The solutions are .
The solutions are
(d) For
, we also consider the intervals:
Using previous tests, it satisfies in:
Using previous tests, it satisfies in:
- The intervals
and .
Therefore, the solution here is:
.
(e) Finally, for
:
The intervals where it is greater or equal to zero, including the roots, gives us:
The intervals where it is greater or equal to zero, including the roots, gives us:
- The solution is:
.
To summarize:
- (a)
- (b)
- ©
- (d)
- (e)

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