Pregunta
Question 2 (1 point) Which electron configuration represents the electrons of an atom of neon (atomic number 10) in an excited state? a \( \quad 2-7-1 \) b \( \quad 2-8-1 \) c \( \quad 2-7 \) d \( \quad 2-8 \)
Ask by Hanson Howell. in the United States
Feb 25,2025
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The correct electron configuration for neon in an excited state is 2-7-1.
Solución
The ground-state electron configuration for neon (atomic number 10) is 2 electrons in the first energy level and 8 electrons in the second energy level (2-8). In an excited state, one of the electrons is promoted to a higher energy level. Removing one electron from the second shell (leaving 7 there) and placing it into a third shell gives the configuration 2-7-1, which still totals 10 electrons.
Thus, the correct answer is (a) 2-7-1.
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In the excited state, electrons can be found in higher energy levels than in their ground state configuration. For neon, the ground state configuration is \( 2-8 \), where all electrons are in the lowest available energy levels. So, if you see a configuration with one or more electrons moved to a higher energy level, that will indicate an excited state. The correct answer for an excited state configuration would be option a \( 2-7-1 \) or b \( 2-8-1 \). Both show the presence of an electron in a higher energy level.
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