Word problem involving the probability of a union In a packet of stickers there are 4 small stars, 9 small rockets, and 10 big rockets. But, there are no big stars. Rafael is going to choose one of these stickers from the packet at random to put on his artwork. What is the probability that the sticker Rafael chooses is big or is a star? Do not round intermediate computations, and round your answer to the nearest hundredth.

To find the probability that Rafael chooses either a big sticker or a star sticker, we first need to identify our total number of stickers and the number of favorable outcomes. Total stickers = 4 (small stars) + 9 (small rockets) + 10 (big rockets) = 23 stickers. Now we calculate the number of big stickers and star stickers: - There are 0 big stars (as stated). - There are 10 big rockets. - There are 4 small stars. The probability of selecting a big sticker (big rockets) or a star sticker (small stars) can be formulated as follows: P(bigger sticker or star) = P(big stickers) + P(star stickers) - P(big stars). Since there are no big stars, P(big stars) = 0. Calculating the individual probabilities: P(big stickers) = Number of big rockets / Total stickers = 10/23, P(star stickers) = Number of small stars / Total stickers = 4/23. Now let's compute the total probability: P(big or star) = P(big stickers) + P(star stickers) - P(big stars) = (10/23) + (4/23) - 0 = (10 + 4) / 23 = 14 / 23. Now, we need to convert this to a decimal and round it to the nearest hundredth: 14 / 23 ≈ 0.6087. When rounded to the nearest hundredth, the final answer is: **0.61.**