Find the values of the following without using a catoulator \( 1.2 .1(-2)^{3} \) \( 1.2 .2(-1)^{200} \) \( 1.2 .3-3 \times(-2)^{2} \) 1.2.4 \( 7^{0} \times 7^{2} \) 1.2.5 \( \left(3 \times 7^{20}\right)^{0} \) \( 1.2 .6 \quad 4^{13} \times 4^{3} \div 4^{16} \) 1.2.7 \( (-5)^{17}+5^{17} \)

To find the values of the given expressions, let’s break them down step by step! 1. **Calculate \( 1.2 .1(-2)^{3} \)**: \( (-2)^{3} = -8 \), so \( 1.2 \times 1 \times -8 = -9.6 \). 2. **Calculate \( 1.2 .2(-1)^{200} \)**: \( (-1)^{200} = 1 \) (since it’s an even exponent). Thus, \( 1.2 \times 2 \times 1 = 2.4 \). 3. **Calculate \( 1.2 .3-3 \times(-2)^{2} \)**: \( (-2)^{2} = 4 \), thus \( 3 \times 4 = 12 \). So, \( 1.2 \times 3 - 12 = 3.6 - 12 = -8.4 \). 4. **Calculate \( 1.2.4 7^{0} \times 7^{2} \)**: \( 7^{0} = 1 \) (any number to the power of 0 is 1), so \( 1 \times 7^{2} = 49 \). 5. **Calculate \( 1.2.5 \left(3 \times 7^{20}\right)^{0} \)**: Again, \( \left(3 \times 7^{20}\right)^{0} = 1 \). 6. **Calculate \( 1.2.6 \quad 4^{13} \times 4^{3} \div 4^{16} \)**: Using properties of exponents, \( 4^{13+3-16} = 4^{0} = 1 \). 7. **Calculate \( 1.2.7 (-5)^{17}+5^{17} \)**: Since \( (-5)^{17} = -5^{17} \), the expression simplifies to \( -5^{17} + 5^{17} = 0 \). To summarize: 1.2.1 = -9.6, 1.2.2 = 2.4, 1.2.3 = -8.4, 1.2.4 = 49, 1.2.5 = 1, 1.2.6 = 1, 1.2.7 = 0.