Find the \( y \)-intercept and the slope of the line. \[ \begin{array}{l}12 x+4 y=4 \\ \text { Write your answers in simplest form. } \\ y \text {-intercept: } \square\end{array} \]
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Bonus Knowledge
To find the \( y \)-intercept and the slope of the line given by the equation \( 12x + 4y = 4 \), we can start by rewriting the equation in the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept. 1. Start with the original equation: \[ 12x + 4y = 4 \] 2. Solve for \( y \): \[ 4y = -12x + 4 \] \[ y = -3x + 1 \] From this equation, we can identify the slope \( m \) as \(-3\) and the \( y \)-intercept \( b \) as \( 1 \). So, the \( y \)-intercept is \( 1 \) and the slope is \(-3\). In simplest form: - \( y \)-intercept: \( 1 \) - Slope: \( -3 \)
