Pregunta
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A bakery sells 11 types of sandwiches. Here are their calorie amounts. \[ 280,593,594,599,611,616,617,617,618,619,946 \] Identify all values that are outliers. If there is more than one outlier, separate them with commas. If there are no outliers, click on "None".

Ask by Chambers Warner. in the United States
Mar 12,2025

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The outliers are 280 and 946.

Solución

We start by sorting the given calorie amounts: \[ 280,\ 593,\ 594,\ 599,\ 611,\ 616,\ 617,\ 617,\ 618,\ 619,\ 946 \] **Step 1: Find the Median (Q2).** With 11 numbers, the median is the 6th value: \[ Q2 = 616 \] **Step 2: Find the First Quartile (Q1).** The lower half (excluding the median) is: \[ 280,\ 593,\ 594,\ 599,\ 611 \] The median of these 5 numbers (the 3rd value) is: \[ Q1 = 594 \] **Step 3: Find the Third Quartile (Q3).** The upper half (excluding the median) is: \[ 617,\ 617,\ 618,\ 619,\ 946 \] The median of these 5 numbers (the 3rd value) is: \[ Q3 = 618 \] **Step 4: Compute the Interquartile Range (IQR).** \[ \text{IQR} = Q3 - Q1 = 618 - 594 = 24 \] **Step 5: Determine the Outlier Boundaries.** - Lower bound: \[ Q1 - 1.5 \times \text{IQR} = 594 - 1.5(24) = 594 - 36 = 558 \] - Upper bound: \[ Q3 + 1.5 \times \text{IQR} = 618 + 1.5(24) = 618 + 36 = 654 \] **Step 6: Identify Outliers.** An outlier is any value below 558 or above 654. Checking the list: - \(280 < 558\), so \(280\) is an outlier. - \(946 > 654\), so \(946\) is an outlier. - All other values lie within the interval \([558, 654]\). **Final Answer:** \(280,946\)

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Extra Insights

To determine outliers in the given set of calorie amounts, we can use the interquartile range (IQR) method. 1. First, let's find the quartiles: - The values sorted in ascending order: \[ 280, 593, 594, 599, 611, 616, 617, 617, 618, 619, 946 \] 2. The median (Q2) is the middle value: - There are 11 values, so the median is the 6th number: \[ Q2 = 616 \] 3. The lower quartile (Q1) is the median of the first half (first 5 values): \[ Q1 = 594 \] 4. The upper quartile (Q3) is the median of the second half (last 5 values): \[ Q3 = 618 \] 5. Calculate the IQR: \[ \text{IQR} = Q3 - Q1 = 618 - 594 = 24 \] 6. Determine the lower and upper bounds for outliers: - Lower bound: \[ Q1 - 1.5 \times \text{IQR} = 594 - 36 = 558 \] - Upper bound: \[ Q3 + 1.5 \times \text{IQR} = 618 + 36 = 654 \] 7. Identify outliers: - Values below 558 or above 654 are considered outliers. - The only outlier above the upper bound is: \[ 946 \] Therefore, the outlier is: 946

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