Solve \( (v-6)^{2}-4=0 \), where \( v \) is a real number. Simplify, your answer as much as possible. If there is more than one solution, separate them with commas. If there is no solution, click "No solution." \[ v=\square \]

To solve the equation \( (v-6)^{2}-4=0 \), we first isolate the squared term: \[ (v-6)^{2} = 4 \] Next, we take the square root of both sides: \[ v-6 = \pm 2 \] This gives us two possible equations to solve for \( v \): 1. \( v-6 = 2 \) 2. \( v-6 = -2 \) For the first equation: \[ v = 2 + 6 = 8 \] For the second equation: \[ v = -2 + 6 = 4 \] Thus, the solutions to the equation are: \[ v = 4, 8 \]