The following formula can be used to determine the quantity of a halo necessary to achieve the concentration required in a protection system Isolate " C " (A) \( C=\frac{100 w s}{V+w s} \) (B) \( C=\frac{100 s}{V-w s} \) (C) \( C=\frac{100}{V s-w s} \) (D) \( C=\frac{100 w s}{100-\bar{C}} \)

To isolate \( C \) in each of the given formulas, we will manipulate the equations step by step. Let's go through each option one by one. ### (A) \( C=\frac{100 w s}{V+w s} \) To isolate \( C \), we can see that \( C \) is already isolated on the left side. Therefore, no further manipulation is needed. ### (B) \( C=\frac{100 s}{V-w s} \) Similar to the first equation, \( C \) is already isolated on the left side. No further manipulation is needed. ### (C) \( C=\frac{100}{V s-w s} \) Again, \( C \) is already isolated on the left side. No further manipulation is needed. ### (D) \( C=\frac{100 w s}{100-\bar{C}} \) In this case, \( C \) is already isolated on the left side as well. No further manipulation is needed. ### Summary - For all options (A), (B), (C), and (D), \( C \) is already isolated. Thus, the isolated form of \( C \) in each case is as follows: - (A) \( C=\frac{100 w s}{V+w s} \) - (B) \( C=\frac{100 s}{V-w s} \) - (C) \( C=\frac{100}{V s-w s} \) - (D) \( C=\frac{100 w s}{100-\bar{C}} \) If you need further assistance or a specific manipulation, please let me know!