What is the passonger speed wrt ground? Ah ceaan liner is travelling \( 18 \mathrm{~km} / \mathrm{h} \) due south. A passenger on the deck malks toward the rear of the ship at \( 3.0 \mathrm{~m} / \mathrm{s} \).

To determine the passenger's speed with respect to the ground, you need to convert the ship's speed into meters per second since the passenger's speed is already given in that unit. The ship travels at \( 18 \, \text{km/h} \), which is equivalent to \( 5 \, \text{m/s} \) (since \( 18 \, \text{km/h} \div 3.6 = 5 \, \text{m/s} \)). Since the passenger walks toward the rear (which is opposite the direction of the ship's travel), you'll subtract the passenger's speed from that of the ship: \( 5 \, \text{m/s} - 3.0 \, \text{m/s} = 2.0 \, \text{m/s} \). Therefore, the passenger's speed with respect to the ground is \( 2.0 \, \text{m/s} \) due south. Now, isn’t it fascinating how velocity combines in this way? Just like two dance partners moving together on a floor, their relative speeds create a whole new rhythm in motion! Understanding relative motion can feel much like navigating through a busy street, where different speeds and directions mix in everyday life, bringing the world to life around us.