According to a report from a particular university, \( 43 \% \) of female undergraduates take on debt. Find the probabifity that none of the female undergraduates have taken on deth if 9 female undergraduates were selected at random. What probability should be found? A., P(2 female undergraduates take on debt) B. P(9 female undergraduates take on debt) C. P(1 female undergraduate takes on debt) TD. P(0 temale undergraduates take on debt) The probability that none of the female undergraduates take on debt is (Type an integer or decimal rounded to three decimat places as needed)

To find the probability that none of the female undergraduates have taken on debt, we can use the complement of the probability that a female undergraduate takes on debt. Given that \( P(\text{debt}) = 0.43 \), the probability that a female undergraduate does not take on debt is \( P(\text{no debt}) = 1 - 0.43 = 0.57 \). Now, since we are selecting 9 female undergraduates, we can find the probability that all of them have not taken on debt. This is calculated as: \[ P(0 \text{ female undergraduates take on debt}) = (P(\text{no debt}))^n = (0.57)^9 \] Calculating this gives: \[ (0.57)^9 \approx 0.025 \] So, the probability that none of the female undergraduates take on debt is approximately **0.025** when rounded to three decimal places.