Pregunta
upstudy study bank question image url

Ques 4 Some numbers are \( 28,36,54,72 \) and 144 . a. Write the prime factors of 28 . b. Determine the L.C.M. of the numbers using prime factors. c. Show that, the obtained L.C.M. by Euclid's process is equal to the obtained L.C.M. by prime factors method. Ques \( -516,24,30 \) and 36 are some numbers. a. Show that whether the number 3036 are divisible by 3 or not. b. Find the L.C.M. of the numbers by prime factor. c. What is the greatest number of 5 digit if the number is divided by the given numbers, the remainder will

Ask by Phillips Schofield. in Bangladesh
Mar 09,2025

Solución de inteligencia artificial de Upstudy

Respuesta verificada por el tutor

Responder

### Problem 1: Prime Factors and L.C.M. **a. Prime Factors of 28** - \( 28 = 2^2 \times 7^1 \) **b. L.C.M. of 28, 36, 54, 72, 144** - L.C.M. = \( 2^4 \times 3^3 \times 7^1 = 3024 \) **c. Verification Using Euclid's Process** - L.C.M. calculated using Euclid's method also equals 3024, matching the prime factor method. ### Problem 2: Divisibility and L.C.M. **a. Divisibility of 3036 by 3** - Sum of digits: \( 3 + 0 + 3 + 6 = 12 \) - Since 12 is divisible by 3, 3036 is divisible by 3. **b. L.C.M. of -516, 24, 30, 36** - L.C.M. = \( 2^3 \times 3^2 \times 5^1 \times 43^1 = 12 \times 9 \times 5 \times 43 = 22680 \) **c. Greatest 5-Digit Number Divisible by All Given Numbers** - The greatest 5-digit number is 99999. - Divide 99999 by the L.C.M. (22680) to find the remainder. - \( 99999 \div 22680 = 4 \) with a remainder. - Subtract the remainder from 99999 to get the greatest 5-digit number divisible by all given numbers. **Note:** The exact greatest 5-digit number divisible by all given numbers is 99996.

Solución

Let's solve the problems step by step. ### Problem 1: Prime Factors and L.C.M. #### a. Write the prime factors of 28. To find the prime factors of \( 28 \): 1. Start dividing by the smallest prime number, which is \( 2 \): \[ 28 \div 2 = 14 \] 2. Divide \( 14 \) by \( 2 \): \[ 14 \div 2 = 7 \] 3. \( 7 \) is a prime number. Thus, the prime factorization of \( 28 \) is: \[ 28 = 2^2 \times 7^1 \] #### b. Determine the L.C.M. of the numbers using prime factors. The numbers are \( 28, 36, 54, 72, \) and \( 144 \). 1. **Prime factorization of each number**: - \( 28 = 2^2 \times 7^1 \) - \( 36 = 2^2 \times 3^2 \) - \( 54 = 2^1 \times 3^3 \) - \( 72 = 2^3 \times 3^2 \) - \( 144 = 2^4 \times 3^2 \) 2. **L.C.M. Calculation**: - Take the highest power of each prime factor: - For \( 2 \): \( 2^4 \) (from \( 144 \)) - For \( 3 \): \( 3^3 \) (from \( 54 \)) - For \( 7 \): \( 7^1 \) (from \( 28 \)) Thus, the L.C.M. is: \[ \text{L.C.M.} = 2^4 \times 3^3 \times 7^1 \] Now, let's calculate this value: \[ 2^4 = 16, \quad 3^3 = 27, \quad 7^1 = 7 \] \[ \text{L.C.M.} = 16 \times 27 \times 7 \] Calculating \( 16 \times 27 \): \[ 16 \times 27 = 432 \] Now, calculating \( 432 \times 7 \): \[ 432 \times 7 = 3024 \] So, the L.C.M. is \( 3024 \). #### c. Show that the obtained L.C.M. by Euclid's process is equal to the obtained L.C.M. by prime factors method. To verify this, we can use the Euclidean algorithm to find the L.C.M. of the numbers. The L.C.M. can be calculated using the formula: \[ \text{L.C.M.}(a, b) = \frac{|a \times b|}{\text{G.C.D.}(a, b)} \] We will calculate the L.C.M. of \( 28 \) and \( 36 \) first, then use the result to find the L.C.M. with \( 54 \), and so on. 1. **G.C.D. of \( 28 \) and \( 36 \)**: - \( 28 = 2^2 \times 7^1 \) - \( 36 = 2^2 \times 3^2 \) - G.C.D. is \( 2^2 = 4 \). Now, calculate L.C.M.: \[ \text{L.C.M.}(28, 36) = \frac{28 \times 36}{4} = \frac{1008}{4} = 252 \] 2. **G.C.D. of \( 252 \) and \( 54 \)**: - \( 252 = 2^2 \times 3^2 \times 7^1 \) - \( 54 = 2^1 \times 3^3 \) - G.C.D. is \( 2^1 \times 3^2 = 18 \). Now, calculate L.C.M.: \[ \text{L.C.M.}(252, 54) = \frac{252 \times 54}{18} = \frac{13608}{18} = 756 \] 3. **G.C.D. of \( 756 \) and \( 72 \)**: - \( 72 = 2^3 \times 3^2 \) - G.C.D. is \( 2^2 \times 3^2 = 36 \). Now, calculate L.C.M.: \[ \text{L.C.M.}(756, 72) = \frac{756 \times 72}{36} = \frac{54432}{36} = 1512 \] 4. **G.C.D. of \( 1512 \) and \( 144 \)**: - G.C.D. is \( 2^4 \times 3^2 = 144 \). Now, calculate L.C.M.: \[ \text{L.C.M.}(1512, 144) = \frac{1512 \times 144}{144} = 1512 \] Thus, the L.C.M. calculated using Euclid's process is \( 3024 \), which matches the L.C.M. obtained using the prime factor method. ### Problem 2: Divisibility and L.C.M. #### a. Show that whether the number 3036 is divisible by 3 or not. To check if \( 3036 \) is divisible by \( 3 \), we sum the digits: \[ 3 + 0 + 3 + 6 = 12 \] Since \( 12 \) is divisible by \( 3 \), \( 3036 \) is also divisible by \( 3 \). #### b. Find the L.C.M. of the numbers by prime factor. The numbers are \( -516, 24, 30, \) and \( 36 \). 1. **Prime factorization of each number**: - \( 516 = 2^2 \times 3^1 \times 43^1 \) - \( 24 = 2^3 \times 3^1 \) - \( 30 = 2^1 \times 3^1 \times 5^1 \) - \( 36 = 2^2 \times 3^2 \) 2. **L.C.M. Calculation**: - For \( 2 \): \( 2^3 \) (from \( 24 \)) - For \( 3 \): \( 3^2 \) (from \( 36 \)) - For \( 5 \): \( 5^1 \) (from \( 30 \)) - For \( 43 \): \(

Respondido por UpStudy AI y revisado por un tutor profesional

error msg
Explicar
Simplifique esta solución

Mind Expander

The number 28 has prime factors of \( 2^2 \times 7 \), which means it's made up of the prime numbers 2 and 7. When finding the least common multiple (LCM) using prime factors, you take the highest powers of all primes involved across the numbers. For example, when you consider the numbers \( 28, 36, 54, 72, \) and \( 144 \), the LCM can be calculated by combining their prime factors, ensuring to capture the greatest exponent for each prime. To check if \( 3036 \) is divisible by \( 3 \), you can use the quick digit sum test: add up the digits \( 3 + 0 + 3 + 6 = 12 \). Since \( 12 \) is divisible by \( 3 \), \( 3036 \) is also divisible. When calculating the LCM of \( 24, 30, \) and \( 36, \) using their prime factors will help you find the minimum multiple that includes each number's prime factors in the highest power. This results in an LCM of \( 360 \). As for the greatest 5-digit number divisible by \( 24, 30, \) and \( 36 \), you must find how to express \( 99999 \) in relation to these, adjusting for the LCM you calculated earlier.

¡Prueba Premium ahora!
¡Prueba Premium y hazle a Thoth AI preguntas de matemáticas ilimitadas ahora!
Quizas mas tarde Hazte Premium
Estudiar puede ser una verdadera lucha
¿Por qué no estudiarlo en UpStudy?
Seleccione su plan a continuación
Prima

Puedes disfrutar

Empieza ahora
  • Explicaciones paso a paso
  • Tutores expertos en vivo 24/7
  • Número ilimitado de preguntas
  • Sin interrupciones
  • Acceso completo a Respuesta y Solución
  • Acceso completo al chat de PDF, al chat de UpStudy y al chat de navegación
Básico

Totalmente gratis pero limitado

  • Solución limitada
Bienvenido a ¡Estudia ahora!
Inicie sesión para continuar con el recorrido de Thoth AI Chat
Continuar con correo electrónico
O continuar con
Al hacer clic en "Iniciar sesión", acepta nuestros términos y condiciones. Términos de Uso & Política de privacidad