Let $$ f(t)=5 t^{4}-7 t+3 e^{t} $$ Then $$ f^{\prime}(t)= $$ Submit Question

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1. We start with the function:
   
   $$
   f(t) = 5t^4 - 7t + 3e^t
   $$

2. Differentiate each term with respect to $$ t $$:

- The derivative of $$ 5t^4 $$ is:
     
     $$
     \frac{d}{dt}(5t^4) = 20t^3
     $$
   
   - The derivative of $$ -7t $$ is:
     
     $$
     \frac{d}{dt}(-7t) = -7
     $$
   
   - The derivative of $$ 3e^t $$ is:
     
     $$
     \frac{d}{dt}(3e^t) = 3e^t
     $$

3. Combine the derivatives:
   
   $$
   f'(t) = 20t^3 - 7 + 3e^t
   $$
$$ f'(t) = 20t^3 - 7 + 3e^t $$

Let \( f(t)=5 t^{4}-7 t+3 e^{t} \) Then \( f^{\prime}(t)= \) Submit Question

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