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essica is setting up tables for the school dance. She has 22 two-liters of pda and 121 bottles of water. She wants an identical amount of soda nd water on each table. (not the same amount of each, but the same mount combined for each table) What is the greatest number of tables e can make if she wants each table to be the same?

Ask by Griffiths Rowe. in the United States
Mar 04,2025

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Jessica can set up 11 tables, with each table having 2 bottles of soda and 11 bottles of water, totaling 13 bottles per table.

Solución

We need to arrange the tables so that each one gets an equal total number of drinks (the combined count of soda and water bottles). Jessica has 22 bottles of soda and 121 bottles of water, and she must split both among the tables without breaking any bottles. Although each table doesn’t have to receive the same number of soda bottles as water bottles, the overall number of bottles at every table must be the same. To do this evenly, the number of tables must be a common divisor of both 22 and 121. In other words, the total numbers (22 and 121) must each be divisible by the number of tables. Step 1. Find the common divisors:  • The positive divisors of 22: 1, 2, 11, 22.  • The positive divisors of 121: 1, 11, 121. Step 2. Identify the greatest common divisor: The common divisors of both are 1 and 11. The greatest of these is 11. Step 3. Verify the distribution: If there are 11 tables,  • Soda: 22 bottles ÷ 11 tables = 2 soda bottles per table.  • Water: 121 bottles ÷ 11 tables = 11 water bottles per table. Each table gets a total of 2 + 11 = 13 bottles, so every table has an identical total. Thus, the greatest number of tables Jessica can set up is 11.

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Beyond the Answer

To determine the greatest number of tables Jessica can set up with an identical amount of soda and water combined, we need to find the greatest common divisor (GCD) of the total amount of each beverage. Jessica has 22 two-liters of soda and 121 bottles of water. The GCD of 22 and 121 is 11. Thus, the greatest number of tables she can set up is 11, meaning each table would receive 2 two-liters of soda (22 ÷ 11) and 11 bottles of water (121 ÷ 11), keeping it fair and balanced for all the tables! Now, let’s imagine the dance buzzing with joyful students enjoying their drinks, with each table offering the perfect refreshment in plentiful amounts! What a fun way to quench everyone’s thirst while they groove to the music!

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