\( 1 \leftarrow\left\{\begin{array}{ll}3 x-2 & \text { if }-3 \leq x \leq 4 \\ x^{3}-4 & \text { if } 4
Ask by Ray Daniel. in the United States
Mar 19,2025
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To find the values of the function \( f \) at the requested points, we can utilize the definition of the piecewise function provided. (a) \( f(0) \): Since \( 0 \) is in the interval \( -3 \leq x \leq 4 \), we use the first piece of the function: \[ f(0) = 3(0) - 2 = -2. \] (b) \( f(1) \): Again, \( 1 \) falls under the first piece, since \( 1 \) is also in the interval \( -3 \leq x \leq 4 \): \[ f(1) = 3(1) - 2 = 3 - 2 = 1. \] Next, we evaluate the remaining values: (c) \( f(4) \): The value \( 4 \) is on the boundary of the first interval, so we still use the first piece: \[ f(4) = 3(4) - 2 = 12 - 2 = 10. \] (d) \( f(6) \): Here, \( 6 \) is greater than \( 4 \) and falls within the second interval \( 4 < x \leq 6 \): \[ f(6) = (6)^3 - 4 = 216 - 4 = 212. \] Thus, the evaluations yield: (a) \( f(0) = -2 \), (b) \( f(1) = 1 \), (c) \( f(4) = 10 \), (d) \( f(6) = 212 \).
