3 Number of oxygen moles required to burn 1 mole of a straight chain alkane completely is determined from the relation .............. "Knowing that $$ n $$ is the number of carbon atoms in this alkane"

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The combustion reaction for a straight chain alkane, whose formula is

$$
C_nH_{2n+2},
$$

can be written as

$$
C_nH_{2n+2} + a\,O_2 \to n\,CO_2 + (n+1)\,H_2O.
$$

**Step 1.** Write down the oxygen atoms produced on the right-hand side:

- Each mole of $$CO_2$$ contains 2 oxygen atoms, so $$ n\,CO_2 $$ gives $$ 2n $$ oxygen atoms.
- Each mole of $$H_2O$$ contains 1 oxygen atom, so $$ (n+1)\,H_2O $$ gives $$ n+1 $$ oxygen atoms.

Total oxygen atoms on the right are

$$
2n + (n+1) = 3n + 1.
$$

**Step 2.** On the left-hand side, oxygen is provided by $$a$$ moles of $$O_2$$, where each mole of $$O_2$$ delivers 2 oxygen atoms. Thus, the total number of oxygen atoms on the left is

$$
2a.
$$

For the reaction to be balanced in oxygen, we equate the number of oxygen atoms on the two sides:

$$
2a = 3n + 1.
$$

**Step 3.** Solve for $$a$$:

$$
a = \frac{3n+1}{2}.
$$

Thus, the number of moles of oxygen required to burn 1 mole of the alkane completely is

$$
\frac{3n+1}{2}.
$$
The number of oxygen moles required to burn 1 mole of a straight chain alkane completely is $$ \frac{3n + 1}{2} $$, where $$ n $$ is the number of carbon atoms in the alkane.

3 Number of oxygen moles required to burn 1 mole of a straight chain alkane completely is determined from the relation .............. "Knowing that \( n \) is the number of carbon atoms in this alkane"

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