If $$ (-7,43) $$ and $$ (4,-12) $$ are two anchor points on a trend line, then find the equation of the line. $$ \qquad y=[?] x+\square] $$

Question

UpStudy AI · Accepted Answer

Let the two anchor points be $$(-7,43)$$ and $$(4,-12)$$.

1. **Calculate the slope ($$m$$)**:

$$
   m=\frac{-12-43}{4-(-7)}=\frac{-55}{11}=-5
   $$

2. **Use the point-slope form of the equation**:

$$
   y - y_1 = m(x - x_1)
   $$

Using point $$(-7,43)$$:

$$
   y - 43 = -5 (x - (-7)) = -5 (x+7)
   $$

3. **Distribute and simplify**:

$$
   y - 43 = -5x -35
   $$

$$
   y = -5x -35 + 43
   $$

$$
   y = -5x + 8
   $$

Thus, the equation of the line is:

$$
y = -5x + 8
$$
The equation of the line is $$ y = -5x + 8 $$.

If \( (-7,43) \) and \( (4,-12) \) are two anchor points on a trend line, then find the equation of the line. \( \qquad y=[?] x+\square] \)