Simplify \( \frac{7}{7^{1 / 3}} \) \( \frac{7}{7^{1 / 3}}=\square \)

We can simplify the expression \( \frac{7}{7^{1/3}} \) by using the laws of exponents. 1. Write \( 7 \) as \( 7^1 \): \[ \frac{7}{7^{1/3}} = \frac{7^1}{7^{1/3}} \] 2. Use the rule for dividing powers with the same base: \[ \frac{7^a}{7^b} = 7^{a-b} \] Here, \( a = 1 \) and \( b = \frac{1}{3} \). Thus: \[ 7^{1-\frac{1}{3}} = 7^{\frac{3}{3}-\frac{1}{3}} = 7^{\frac{2}{3}} \] So, the simplified form is: \[ \boxed{7^{\frac{2}{3}}} \]