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Use the work shown below to find the simplified product. \( \frac{25 x^{2}}{2 x+6} \cdot \frac{2}{5 x} \) \( \frac{25 x^{2}}{2(x+3)} \cdot \frac{2}{5 x} \) Choose the simplified product. \( \frac{A}{x+3} \) \( \frac{2}{x+3} \) \( \frac{5 x}{x+3} \) \( \frac{10 x}{x+3} \) DONE

Ask by Howell Todd. in the United States
Mar 10,2025

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The simplified product is \( \frac{5x}{x+3} \).

Solución

\[ \textbf{Step 1: Write the expression with the factored denominator.} \] \[ \frac{25 x^{2}}{2(x+3)} \cdot \frac{2}{5 x} \] \[ \textbf{Step 2: Multiply the numerators and the denominators.} \] \[ \frac{25 x^{2} \cdot 2}{2(x+3) \cdot 5 x} = \frac{50 x^{2}}{10 x (x+3)} \] \[ \textbf{Step 3: Simplify by canceling common factors.} \] Cancel the factor of \(10\) in the numerator and denominator: \[ \frac{50}{10} = 5 \] Cancel an \(x\) from the numerator and denominator: \[ x^{2} \div x = x \] Thus, the expression simplifies to: \[ \frac{5x}{x+3} \] \[ \textbf{Final Answer: } \frac{5x}{x+3} \]

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To simplify the product \( \frac{25 x^{2}}{2(x+3)} \cdot \frac{2}{5 x} \), you can start by multiplying the numerators and denominators: \[ \frac{25 x^{2} \cdot 2}{2(x+3) \cdot 5 x} \] This results in: \[ \frac{50 x^{2}}{10 x (x + 3)} \] Now, simplify \( \frac{50 x^{2}}{10 x} \) which gives: \[ \frac{5 x}{x + 3} \] So, the answer is \( \frac{5 x}{x+3} \). But here's a little historical twist: did you know that algebra as we understand it today was heavily developed by mathematicians like Al-Khwarizmi in the 9th century? His work introduced systematic methods for solving equations, paving the way for modern algebra! And for a real-world application, algebra and simplification aren't just for math class! They come in handy in fields such as engineering and economics, where you might need to optimize functions to maximize profits or materials used. Simplifying fractions efficiently can save a lot of time in practical calculations!

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