Find the slope and \( y \)-intercept of the line. \[ \frac{1}{4} x-\frac{1}{5} y+1=0 \]

To find the slope and \( y \)-intercept of the line given by the equation \( \frac{1}{4} x - \frac{1}{5} y + 1 = 0 \), we can rearrange it into the slope-intercept form \( y = mx + b \), where \( m \) is the slope and \( b \) is the \( y \)-intercept. Starting with the original equation: \[ \frac{1}{4} x - \frac{1}{5} y + 1 = 0 \] We can isolate \( y \) on one side: 1. Move \( \frac{1}{4} x \) and \( 1 \): \[ -\frac{1}{5} y = -\frac{1}{4} x - 1 \] 2. Multiply through by \(-5\) to eliminate the fraction in front of \( y \): \[ y = \frac{5}{4} x + 5 \] Now, the equation is in slope-intercept form. From this, we can identify: - The slope \( m = \frac{5}{4} \) - The \( y \)-intercept \( b = 5 \) So, the slope is \( \frac{5}{4} \) and the \( y \)-intercept is \( 5 \).